
Imagine I ask you to draw a triangle whose sides are exactly 5 cm, 7 cm and 6 cm. Could you draw it exactly, with no guessing and no eyeballing, so that every side comes out the right length? The tricky part is getting all three sides right at the same time.
Take two or three hands-up ideas, then hold the question open: can we get all three sides right at the same time? Do not reveal the arc trick yet — that is the discovery of the next step.
Watch three constructions built with a compass and ruler only. In the first, we draw the longest side. Then we swing an arc from each end. Where the two arcs cross is the third corner. In the second, we cut a line exactly in half. In the third, we cut an angle exactly in half. Watch where each arc crosses, because those crossing points are what make the construction exact.
Work each one live on the board — do not read a script.
Hold out for the crossing points as the key idea — that is what makes it precise rather than a guess.
Now let us build the triangle together. Watch it appear on the board first: draw the 7 cm base, swing the 5 cm arc from one end and the 6 cm arc from the other, then mark the crossing point. Once you have watched it on the board, build the same triangle (sides 5 cm, 7 cm and 6 cm) at your desk.
Keep the compass point pressed firmly on the dot so it does not move. Do not change the width once it is set. Swing only the pencil-arm to trace each arc.
Model the triangle on the board first, then let pupils build it at their desks — do not ask them to draw and watch at the same moment.
Run the circle-tool in explore mode on the IWB so the arc-swing mirrors the paper work. Invite one or two pupils up to demonstrate the set-plant-rotate hold before the class draws. Then circulate as pupils draw and catch the compass slipping — the single most common slip is the point drifting mid-swing.
The two bisections are demonstrated on the board here and practised in the Class Challenge, so keep this step on the triangle only.
In your maths copy, construct a triangle with sides 6 cm, 8 cm and 10 cm using your compass and ruler only — no protractor, pure construction. Mark each arc lightly with the compass and circle the third vertex where the arcs meet. Underneath, write: this is a right-angled triangle. The reason (6² + 8² = 100 = 10²) is a next-year idea, so you do not need to work it out today.
Walk the room glancing for the base drawn first and the arcs meeting cleanly — this is whole-class copybook practice, not marking. The 6²+8²=10² note is a Pythagorean teaser for next year; do not stop to explain it fully.
Now we construct these on the board, one at a time, and every pupil builds the same one on paper. We check each one before moving on:
Fast finishers who are watching the board: construct an equilateral triangle with side 8 cm (all three sides equal) and predict its three angles before we measure them.
This is the practice round — pupils take turns at the board, check each answer, and the class confirms before moving on. Keep the board work brisk rather than over-explaining.
Every pupil builds all three listed constructions on paper. Run the circle-tool construction challenges on the IWB alongside. The 90°-bisection is the investigation beat: pupils use their protractor to confirm each half is 45° — this is where the compass-precision claim gets tested against a measuring tool.
Stretch for fast finishers who are watching the board: construct an equilateral triangle (side 8 cm), predict all three angles are 60°, and be ready to explain why they must be equal.
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