Mathematics
Intermediate
50 mins
Teacher/Student led
+65 XP
What you need:
IWB/Projector/Large Screen
Square tiles

Comparing Area and Perimeter

Explore how two shapes can cover the same area but have different perimeters. You'll measure area by counting squares and perimeter by adding side lengths, discovering that the way a shape is arranged changes the distance around its edge.

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    1 - Getting Started ~4 mins

    Illustration for Getting StartedHere are two rectangles drawn on squared paper.

    • Rectangle A: a long thin strip, 1 square tall and 6 squares long.
    • Rectangle B: a chunky block, 2 squares tall and 3 squares long.

    Count the squares inside each one.

    Now have a think before we work anything out: if an ant walked all the way around the edge of each one, would it walk the same distance both times? Hands up for your guess.

    2 - Watch and Notice ~9 mins

    Let's look at these rectangles together. For each one, count the squares that fit inside (that is the area) and then walk right around the edge, adding every side (that is the perimeter). The first two shapes cover the same area, so watch what happens to the distance around. The third one is a bigger shape where both the area and the perimeter are different, so keep an eye on both numbers.

    3 - Draw the Two Rectangles in Your Copy ~3 mins

    COPYBOOK MOMENT

    Illustration for Draw the Two Rectangles in Your CopyIn your squared copy, draw two different rectangles that each cover 8 squares. Write the perimeter beside each one, then ring the rectangle with the longer way around.

    4 - Try It Together ~8 mins

    Today we build these rectangles on one shape-measurer. We drag the corners to change each shape into the next. We will work three shapes in turn. First a 2 by 4 rectangle. Then a 1 by 8. Then a 3 by 3. For each one, count the area inside. Then add the sides for the perimeter. Say out loud whether the distance around is getting longer or shorter as the shape changes.

    Shape Measurer

    5 - Class Challenge ~8 mins

    Key point

    Here is the investigation. Each time, use exactly 12 square tiles. Where you have your own tiles, work on your own; where a group of four shares one set of 12, take turns arranging them. Make as many different rectangles as you can and write down the area and the perimeter of each one.

    • First, make any rectangle from all 12 tiles and record its area and perimeter.
    • Then find a second, different rectangle from the same 12 tiles.
    • Which of your rectangles has the smallest distance around?
    • Explain why the area stayed 12 every single time while the perimeter kept changing.

    Using exactly 12 square tiles each time, how many different rectangles can you make, and what is the area and perimeter of each?

    Give each pupil 12 square tiles (or 12 shaded squares on squared paper) where possible; where tiles are short, seat pupils in groups of four sharing one set of 12 and take turns. They arrange all 12 into a rectangle, record the sides, the area and the perimeter, then rearrange into a different rectangle and record again. Repeat to find every rectangle possible from 12 tiles (1 by 12, 2 by 6, 3 by 4). Individual pupils bring one rectangle to the board to record its measurements for the class.

    1. Make any rectangle from all 12 tiles and record its area and perimeter.
    2. Find a second, different rectangle from the same 12 tiles.
    3. Which of your rectangles has the smallest distance around?
    4. Why did the area stay 12 every time while the perimeter changed?

    Ways to start:

    • Lay all 12 tiles in a single long row — what are the sides of that rectangle?
    • Try two rows of 6 tiles — how does the shape look now?

    Stretch:

    • Put your rectangles in order from the longest way around to the shortest — what do you notice about their shapes?
    • If you had 16 tiles instead, which rectangle would have the shortest perimeter?

    Record: table with columns: sides (e.g. 2 by 6), area (squares), perimeter (units)

    Answers & strategies (teacher)
    1. Make any rectangle from all 12 tiles and record its area and perimeter. — For example 2 by 6: area 12 squares, perimeter 2 + 6 + 2 + 6 = 16.
    2. Find a second, different rectangle from the same 12 tiles. — 3 by 4: area 12 squares, perimeter 3 + 4 + 3 + 4 = 14 (or 1 by 12: area 12, perimeter 26).
    3. Which of your rectangles has the smallest distance around? — The 3 by 4 rectangle, with a perimeter of 14 — the chunkiest rectangle has the shortest way around.
    4. Why did the area stay 12 every time while the perimeter changed? — The 12 tiles never went away, so the space covered (area) stayed 12; but spreading them into a long thin shape puts more tile edges on the outside, making the distance around longer.
    Pupil practice
    Module 5 · Area, Perimeter and Volume Measures
    Lesson 57 · Comparing Area and Perimeter
    Download Activity Book page (PDF)
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